xy = 120, x^2 + y^2 = 289. Use (x+y)^2 = x^2 + y^2 + 2xy = 289 + 240 = 529. Thus, x+y = √(529) = 23.
xy = 120, x^2 + y^2 = 289। (x+y)^2 = x^2 + y^2 + 2xy = 289 + 240 = 529 का उपयोग करें। अतः, x+y = √(529) = 23।