$A = P(1 + R/100)^n$ => $6050 = 5000(1 + R/100)^2$ => $1.21 = (1 + R/100)^2$ => $1.1 = 1 + R/100$ => $R = 10\%$.
$A = P(1 + R/100)^n$ => $6050 = 5000(1 + R/100)^2$ => $1.21 = (1 + R/100)^2$ => $1.1 = 1 + R/100$ => $R = 10\%$।